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=0.4Y-0.05Y^2
We move all terms to the left:
-(0.4Y-0.05Y^2)=0
We get rid of parentheses
0.05Y^2-0.4Y=0
a = 0.05; b = -0.4; c = 0;
Δ = b2-4ac
Δ = -0.42-4·0.05·0
Δ = 0.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.4)-\sqrt{0.16}}{2*0.05}=\frac{0.4-\sqrt{0.16}}{0.1} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.4)+\sqrt{0.16}}{2*0.05}=\frac{0.4+\sqrt{0.16}}{0.1} $
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